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Re: independent sum of two columns causes the performance down apparently.

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     only 3 columns, id1,id2 are string, num is a double. I use id1 to join.

    

      while executing this,

     select a.id2 m, b.id2 n, count(*)

     from t a, t b

     where a.id1=b.id1

     group by a.id2, b.id2;

 

     it takes 7s.

 

 

     when executing this,

 

     select a.id2 m, b.id2 n, count(*), sum(a.num)

     from t a, t b

     where a.id1=b.id1

     group by a.id2, b.id2;

 

     it takes 8s.

 

     while executing this,

     select a.id2 m, b.id2 n, count(*), sum(a.num), sum(b.num)

     from t a, t b

     where a.id1=b.id1

     group by a.id2, b.id2;

 

      it takes 16s.

    

     as my understanding of HANA, the last query should take only about 9s.


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